Giải:
\(\underset{x\rightarrow -2}{lim}\) \(\frac{4-x^{2}}{x + 2}\) = \(\underset{x\rightarrow -2}{lim}\) \(\frac{ (2-x)(2+x)}{x + 2}\) = \(\underset{x\rightarrow -2}{lim} (2-x) = 4\).
Giải:
\(\underset{x\rightarrow -2}{lim}\) \(\frac{4-x^{2}}{x + 2}\) = \(\underset{x\rightarrow -2}{lim}\) \(\frac{ (2-x)(2+x)}{x + 2}\) = \(\underset{x\rightarrow -2}{lim} (2-x) = 4\).
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