Giải:

\(\underset{x\rightarrow 6}{lim}\) \(\frac{\sqrt{x + 3}-3}{x-6}\) = \(\underset{x\rightarrow 6}{lim}\) \(\frac{(\sqrt{x + 3}-3)(\sqrt{x + 3}+3 )}{(x-6) (\sqrt{x + 3}+3 )}\) = \(\underset{x\rightarrow 6}{lim}\) \(\frac{x +3-9}{(x-6) (\sqrt{x + 3}+3 )}\) = \(\underset{x\rightarrow 6}{lim}\) \(\frac{1}{\sqrt{x+3}+3}\) = \(\frac{1}{6}\).


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